53. Find the number of ways in whic...
Question  # 53. Find the number of ways in which arrangements of 4 letters can be made from the word "MATHEMATICS. (a) 1,680 (b) 756 (C) 18 (d) 2454

Other Exams
Maths
Solution 64 4.0 (1 ratings)  In marthematics ( n O cdot ) of ( r A=2 ) no. of ( T=2 ) no. ( A=2 ) ofter luters ( forall, E, I, c, s ) are sinfle letters alike ond two alik case ( 1-T w_{0} ) We have 3 groups of same luters ( i cdot e cdot 2 M cdot s, 2 T^{prime} s ) ard ( 2 A_{S}^{prime} ) ad we have to sulet two out so this can be dom in ( 3 C_{2} ) two different. here ir this owt of 7 group ( i cdot f cdotleft(2 text { pes } 27^{circ} ) sent. right. ( 7 c_{2}+3 c_{1} ) ( mid cos x-3] ) all diffirent differet letors ( quad M, T, A_{1} H, E, I, C S ) this cun be don in 8 cumay Arrarginent - for ist con. ( frac{4 !}{2 ! 2 !} ) for ( i^{-d} cos frac{4 !}{2 !} ) dor third con cil. final anw ( -3 c_{2} frac{x q !}{2 ! 2 !}+3 c_{1} times 7 c_{2} times frac{4 !}{2 !}+8 c_{4} times 4 ! ) ( 18+756+1680=2454 ) Quick and Stepwise Solutions Just click and Send OVER 20 LAKH QUESTIONS ANSWERED Download App for Free