Question

We know,
R tan ( theta=4 mathrm{H} )
now ( sqrt{3} ) Han ( theta=9 mathrm{H} )
tan ( theta=frac{1}{sqrt{3}} )
( theta=30^{circ} )
Ans ( (a) 80^{circ} )

# 53. The horizontal range of projectile is 4v3 times the maximum height achieved by it, then the angle of projectile with the horizontal is: (a) 30° (b) 45° (c) 60° (d) 900

Solution