Question

Let 'v' be the initial velocity of projection. ( E=1 / 2 mathrm{mv}^{2} )
At top, the velocity is ( u=v cos (30)= ) ( (sqrt{3} / 2) mathrm{v} )
( mathrm{K.E}_{2} ) at top ( =1 / 2 mathrm{m}[(sqrt{3} / 2) mathrm{v}]^{2}=(3 / 4)[1 / 2 )
( left.m v^{2}right]=3 E / 4 )

# 55 A body is projected at an angle of 30° to the horizontal with kinetic energy K. Then its kinetic energy at the topmost point is (b) (d) zero

Solution