Question

( begin{array}{ccc}x & x+y & x+y+z 2 x & 5 x+2 y & 7 x+5 y+2 z 3 x & 7 x+3 y & 9 x+7 y+32 R_{2} rightarrow R_{2}-2 R_{1} & 4 R_{3} rightarrow R_{3}-3 R_{3}end{array} )
( x quad x=frac{x+y}{3 x+0} frac{x+y+2}{5 x+3 y}=-16 )
( 0 quad 4 x+0 quad 6 x+4 y )
( x[(3 x)(6 x+4 y)-(4 x)(5 x+3 y)]=-16 )
( x^{2}[18 x+12 y-20 x-12 y]=-16 )
( x^{2}[-2 x]=-16 )
( 2 x^{3}=16 Rightarrow x^{3}=8 Rightarrow(x=2 )

# 59. If x, y and Z e R, and ixx +y x+y+2 | A= 2x 5x + 2y 7x + 5y + 2z = -16, then find value of x. 13× 7x + 3y 9x + 7y + 3z|

Solution