6. 15.2X+1 +15.2-x+2 = 135
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6. 15.2X+1 +15.2-x+2 = 135

JEE/Engineering Exams
Maths
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( mid 5 cdot 2 cdot 2+15 cdot frac{2^{2}}{2^{2}}=135 ) Let ( 2^{2}=t ) 2) ( 30 t+frac{60}{t}=135 ) ( Rightarrow quad 5 t+frac{12}{2}=27 ) ( Rightarrow 6 t^{2}-27 z+12=0 ) ( Rightarrow quad 6 t^{2}-24 z-3 z+12=0 ) ( Rightarrow(6 z-3)(z-4)=0 ) ( therefore t=frac{1}{2} sin 4 ) ( begin{aligned} therefore 2^{x}=2^{-1} & text {on } 2^{x}=2^{2} therefore x=-1 & Rightarrow x=2 end{aligned} ) ( therefore x=-1,2 )
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