Question 
het the
e total sum ( =x )
[
begin{aligned}
Rightarrow mid 4 k+17 k+19 k &=x
50 k &=x
end{aligned}
]
a but The amount was divided in
me latio 8: 9: 13
[
begin{array}{l}
Rightarrow quad 8 p+9 p+B p=x
Rightarrow quad 30 p=x-Q
end{array}
]
Now Charan got mare beeaume of
one wrong distnbution
[
begin{array}{l}
Rightarrow quad 13 p-19 k=1000344
Rightarrow 13left[frac{n}{30}right]-19left[frac{n}{50}right]=100.344
rightarrow frac{65 n-57 n}{150}= 244
end{array}
]
-1
[
frac{8 x}{150}=
]
[
8 times
]
5
( 483 times 150 )
( times 2344 times 150 )
80 ( quad sqrt{1 times 2} )
( =6450 ) 
117 
4.0 (1 ratings) 
Share
6. A certain sum was to be divided among Akash, Brijoy and Charan in the ratio of 14 : 17 : 19 but erroneously it was divided in the ratio of 8:9:13, and so, Charan got 344 more. What was the total amount distributed among the three? 141 76 A50 * Goo 20 20
Solution 
Share 117 4.0 (1 ratings)
Share 117 117Rate Solution 
Share
Relevant Questions
Recent Questions
