Question

G. The process is isothermal expansion, hence
[
begin{aligned}
q &=-W
Delta E &=0
W &=-2.303 n R T log frac{V_{2}}{V_{1}}
&=-2.303 times 0.04 times 8.314 times 310 times log frac{335}{50}
&=-208 mathrm{J}
q &=+208, quad W=-208 quad text { (expansion work) }
end{aligned}
]

# 6. A piston filled with 0.04 mole of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0°C. As it does so, it absorbs 208 J of heat. The values of q and W for the process will be (R = 8.314 J/mol K, In 7.5 = 2.01) (2013 Main) (a) q = + 208 J, W = - 208 (b) q = - 208 J.W = - 208 (c) q= -208, W = + 208 (d) q= + 208 J, W = + 208 J

Solution