Question

6. (2) Length of wire = Perimeter of rectangle
[
begin{array}{l}
=2(42.7+21.8)=2 times 64.5
=129.0 mathrm{m}
end{array}
]
Again, perimeter of square = Length of wire
[
begin{aligned}
4 x operatorname{side} &=129
therefore quad & text { side }=frac{129}{4}=32.25 mathrm{m}
end{aligned}
]

# 6. A wire is in the shape of a rectangle. Its length is 42.7 m and breadth is 21.8 m. If the same wire is re-bent in the shape of a square, what will be the measure of the side of the square? RRB NTPC (Phase I) 2016 (1) 16.125 (2) 32.25 (3) 11.35 (4) 22.70

Solution