6. Given that H.C.F of (306, 657) =...
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6. Given that H.C.F of (306, 657) = 9, find the L.C.M. of (306,657).

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begin{aligned}( H C F times L C M &= ) product of 2 nos ( 9 times L(M) &=306 times 657 & frac{L C M}{L C M}=34 times 657 )hline( L C M &=22338 end{aligned} )
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