Question

6. (3) Let the numbers be ( 4 x ) and ( 4 y . ) Then Ist number ( times ) IInd number ( =mathrm{HCF} times mathrm{LCM} )
[
begin{array}{c}
4 x times 4 y=4 times 4 times 5 times 7
x times y=5 times 7
end{array}
]
Hence, Ist number ( =4 times 5=20 ) and IInd number ( =4 times 7=28 )
( therefore quad ) Smaller number ( =20 )

# 6 The HCF of two number is 4 and the two other factors of LCM are 5 and 7. Find the smaller of the two numbers. RRB NTPC (Phase I) 2016 (1) 10 (2) 14 (3) 20 (4) 28

Solution