65. 1b²c? bc b + c) caz ca cta = 0 ...
Question

# 65. 1b²c? bc b + c) caz ca cta = 0 la?62 ab atbl

11th - 12th Class
Maths
Solution
42
4.0 (1 ratings)
( left|begin{array}{ccc}b^{2} c^{2} & b c & b+c c^{2} a^{2} & c a & c+a a^{2} b^{2} & a b & a+bend{array}right|=0 ) apply the row opelotiond ( left{begin{array}{ll}frac{a}{a} b_{c}^{v} v & frac{a}{a} b c frac{a(b+c)}{a} frac{b c_{a}^{2}}{b} & frac{b(c a)}{b} frac{b(c+a)}{b} frac{c a^{2} b^{2}}{c} & frac{c a b}{c} frac{c(a+b)}{c}end{array} begin{array}{c}R_{1} rightarrow frac{a}{a} R_{1} R_{2} rightarrow frac{b}{b} R_{2} R_{3} rightarrow frac{c}{c} R_{3}end{array}right. ) ( frac{1}{4} ) ( =frac{1}{a b c}left|begin{array}{lll}a b^{2} c a b c & a(b+c) b c^{2} a^{2} a b c & b(c+a) c a^{2} b^{2} & a b c & c(a+b)end{array}right| ) ( - ) Hor taken Out colum O E colum ( Rightarrow quad frac{(a b c)(a b c)}{a b c}left|begin{array}{ccc}b c & 1 & a b+a c a c & 1 & b c+b a a b & 1 & c a+b cend{array}right| ) pry ( c_{1}+c_{3} rightarrow c_{3} ) ( Rightarrow quad a b c|b c quad| a b+b c+a c mid ) ( a c quad 1 quad a b+b c+a c ) ( a b quad 1 quad a b+b c+a c ) ( =frac{a b+b c+a c}{a b c}left|begin{array}{ccc}b_{l} & 1 & 1 a c & 1 & 1 a b & 1 & 1end{array}right| ) ( a b+b a-a c ) Har ( c_{2}=c_{3} ) According To PLopertit feaminedt ( =0 ) any the tao rows or) adumns ale same then determinad is ( thereforeleft|begin{array}{lll}b^{2} c^{2} & b c & b+c c^{2} a^{2} & c a & c+a a b^{2} & a b & a+bend{array}right|=0 )