Question

Initially the pocket has only horizontal
velocity equal to u
When it reaches the ground it has
horizontal velocity u and vertical velocity
( sqrt{2 g h} )
Therefore resultant velocity
( =sqrt{u^{2}+2 g h} )
Hence a is the correct answer

# 65. An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earth's surface will be (g is acceleration due to gravity) (a) Vu? +2gh (b) /2gh (c) 2gh (d) Ju -28h . 1 1 .11

Solution