Question

7. (0) 9 +27 If X-1 +(x-1) + Vx? --3x + 2 = 0, then value of x is : (B)4 (C)-2 (A) 1 (D) None of these

JEE/Engineering Exams

Maths

Solution

230

4.0 (1 ratings)

( operatorname{son}(7) quadleft(x^{2}-1right)+(x-1)^{2}+sqrt{x^{2}-3 x+2}=0 ) Apply elimination metwo o a) ( quad ) if ( x=1 ) ( 0+0+sqrt{1-3+2}=0 ) hence satisfly ( left(x^{2}right) ) ( (b) ) ( x=4 quad|16-1|+(3)^{2}+sqrt{16-12+2}= ) ( Rightarrow 15+9+sqrt{6} eq 0 ) Not solu 2 ( x=-2 ) ( therefore quad|3|+(-5)^{2}+sqrt{4+6+2} eq ) thus Not do 14 ( therefore sqrt{A v}=x^{2} 1 )