Question

Partial pressure of I atoms ( =mathrm{P} 1=40 / 100 times mathrm{P} )
total
( =40 / 100 times 10^{5} )
( =4 times 10^{4} mathrm{Pa} )
Partial pressure of ( mathrm{I}_{2} ) molecules, ( mathrm{PI}_{2}=60 / 100 times mathrm{P} ) total
( =60 / 100 times 10^{5} )
( =6 times 10^{4} mathrm{pa} )
now for the given reaction, ( mathrm{Kp}=(mathrm{pl})^{2} / mathrm{PI}_{2} )
( =left(4 times 10^{4}right)^{2} / 6 times 10^{4} )
( =2.67 times 10^{4} mathrm{Pa} )

# 7.3 At a certain temperature and total pressure of 10°Pa, iodine vapour contains 40% by volume of I atoms I, (g) = 21 (9) Calculate K, for the equilibrium.

Solution