Question
Let constant acceleration is a
distance travels in 20 seconds
( s=0^{*} 20+a^{*} 20^{2} / 2 )
( s=200 a )
distance travels in first 10 seconds
( s 1=0^{*} 10+a^{*} 10^{2} / 2 )
s1 ( =50 a ) distance travels in next 10 seconds
( s 2=s-s 1 )
( s 2=200 a-50 a=150 a )
( s 2 / s 1=150 a / 50 a=3 )

7. A particle after starting from rest, experiences constant acceleration for 20 sec. If it covers a distance si in first 10 sec, then the distance covered during next 10 sec will be (1) Si (2) 251 (3) 351 (4) 451
Solution
