Question

( (2 sqrt[2]{2})^{2} )
( operatorname{dis}^{1 / 2}=frac{sqrt{(pi R)^{2}+2 R}}{R sqrt{pi^{2}+4}}^{2} )

# 7. A wheel of radius Rrolls forward half a revolution. The displacement of a point which is at height from the point which is initially in contact to the ground is (1) RT +4 (3) TR+ 2R (2) TR (4) 2R

Solution