Question

7 | L on व ५ - 7 ५ ।।। ५ ६ मान 41 ) ।

Defence Exams

Maths

Solution

135

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( sqrt{x}+y=7, x+sqrt{y}=11 ) Let ( sqrt{x} ) and ( sqrt{4} ) be a and ( b ) ( a+b^{2}=7 ) ( a=7-b^{2} ) Putting value in ( x+sqrt{y}=a^{2}+b=11 ) ( left(7-b^{2}right)^{2}+b=12 ) ( 49+64=14 mathrm{b}^{2}+mathrm{b}=1 mathrm{L} ) ( b^{4}-14 b^{2}+b+38=0 ) By. hit and tijal method Factor of ( 30=2 times 2 times 19 ) If we ( p 452 ) on beloce ( (2)^{4}-14 times(2)^{2}+2+30=0 ) [ 26-14 times 4+40=0 ] ( 16-56+40=0 ) ( 56+56=0 ) [ b=2 ] ( 9=7-4 ) ( 9=3 ) ( 3 c=9, y=4 )