7. The The number of values of x in...
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7. The The number of values of x in the interval [0, 51] satisfying the equation 3 sin2 x - 7 sin x + 2 = 0 is (B) 5 (A) O

JEE/Engineering Exams
Maths
Solution
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Let ( sin x=t ) ( 32^{3} t^{2}-7 z+2=0 ) ( 2 y quad 3 z^{2}-6 z-t+2=0 ) 2) ( (3 z-1)(z-2)=0 ) ( Rightarrow quad t=frac{1}{3}, 2 ) ( therefore sin x=frac{1}{3} ) a ( sin x=2 x_{text {becaun }} ) sinn 31 ( sin n=frac{1}{3} ) ( therefore x=n pi+(-1)^{n} sin ^{-1} frac{1}{3} quad(0,2 pi) quad(2 pi, 4 pi) mid 4 pi 9 ) ( therefore ) no. of ( operatorname{seln} i n[0,5 pi]=2+2+2 ) ( =6 ) give rating
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