Question

( sin ^{2} theta )
( operatorname{mig} )
( m_{2} g sin theta-T-mu m_{2} g cos theta=m_{2} a )
(11) ( +T+m_{1} g sin theta-mu m_{1} g cos theta=m_{1} q )
( (0+12)+2-4+24-8=69 )
( =5 )
( 24=69 )
( Rightarrow quad a=4 mathrm{m}left(mathrm{s}^{2}right. )
( -2 y(1,12-4-T=8 )
( Rightarrow quad T=0 )
"s Qprom A

# 7 Two blocks m = 4kg and m2 = 2kg, connected by a weightless rod on a plane having inclination of 37° as shown in figure. The coefficients of dynamic friction of m, and m, with the inclined plane are u = 0.25. Then the common acceleration of the two blocks and the tension in the rod are: (A) 4 m/s2, T = 0 (B) 2 m/s2, T = 5 N (C) 10 m/s2, T = 10 N (D) 15 m/s2, T = 9N

Solution