Question

gext is dubined ito ( phi(x+1) ) is difined. Thus thr domain is all ( xlceil x+1 in[0,2] rightarrow ) begin{tabular}{l}
( x in[-1,1] )
hline domain
end{tabular}
Quuce of ( e(x+1) in[0,1] )
( 2-f(x+1) in[-1,0] )
( therefore quad g(x)=1-f(x+1) in[0,] ) is ( frac{text { dange }}{0} )

# 8. A function f has domain (-1,2] and range [0, 1]. Find the domain and range of the function g defined by g(x) = 1 - f(x + 1).

Solution