Question

( left(1-3 w+w^{2}right)left(1+w-3 w^{2}right) )
( 1+w+w^{2}=0 )
( therefore 1+w^{2}=-w, 1+w=-w^{2} )
( left(1+w^{2}-3 wright)left(1+w-3 w^{2}right) )
( (-omega-3 w)left(-w^{2}-3 w^{2}right) )
( (-4 w)left(-4 w^{2}right) )
( 16 w^{3}=16(1)=16 mu )

# 8. Simplify: (1 - 30 + m2)(1 +0 -30°).

Solution