Question

( begin{aligned} A rightleftharpoons & B Delta G^{circ} &=Delta H^{circ}-T Delta S^{circ} Delta G^{circ} &=-2.303 R T log K log K &=frac{Delta H^{circ}-T Delta S^{circ}}{-2.303 R T} &=frac{-54.07 times 10^{3}-298 times 10}{-2.303 times 8.314 times 298} &=frac{-57050}{-5705}=10 end{aligned} )

# 8. The value of log10 K for a reaction A Bis (Given : A,H° = - 54.07 kJ moll, A,S°298 = 10 - moll and R = 8.314 JK-'moll: 2.303 X 8.314 x 298= 5705) (2007, 3M) (2) 5 (b) 10 (C) 95 (d) 100

Solution