86. cot 54°tan 20° tan 36° cot 70°
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86. cot 54°tan 20° tan 36° cot 70°

JEE/Engineering Exams
Maths
Solution
192
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( frac{cot 54^{circ}}{tan 36^{circ}}+frac{tan 20^{circ}}{cot 70^{circ}} ) ( frac{cot left(90-36^{circ}right)}{tan 36^{circ}}+frac{tan 20^{circ}}{cos left(90^{circ}-20^{circ}right)} ) ( =frac{tan 36^{circ}}{tan 36^{circ}}+frac{tan 20^{circ}}{tan 20^{circ}} ) ( =1+1=2 tan ^{2} )
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