Question

( y=-1 )
( y^{2}=(-1)^{2}=1 )
( y^{3}=(-1)^{3}=-1 )
( y^{4}=(-1)^{4}=1 )
( y^{5}=(-1)^{5}=1 )( quad 1+frac{1}{y}+frac{1}{y^{2}}+frac{1}{y^{3}}+frac{1}{y^{4}}+frac{1}{y^{2}} )
( y^{prime}+(-1)+x+(1)+x+k^{prime}=0 )

# 9. If y=-1, then the value of 1+(1/y)+(l/y2)+(l/y3) +(1/y4)+(1/y) is (1)-1 (3) 1 (4) 2 (2) 0

Solution