9. In the following figure AC = 10 ...
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9. In the following figure AC = 10 & BD = 14, then area of quadrilateral ABCD - (A) 70/3 (B) 1403 (C)35 13 (D) 70

JEE/Engineering Exams
Maths
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( begin{aligned} A r cdot &=frac{1}{2} times 10 times 14 times 51 n mid 20 &=70 times 51 nleft(90+30^{1}right) &=70 times(0530 &=70 times frac{sqrt{3}}{2} end{aligned} )
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