Question

9. In the following figure AC = 10 & BD = 14, then area of quadrilateral ABCD - (A) 70/3 (B) 1403 (C)35 13 (D) 70

JEE/Engineering Exams

Maths

Solution

1.5 (2 ratings)

( begin{aligned} A r cdot &=frac{1}{2} times 10 times 14 times 51 n mid 20 &=70 times 51 nleft(90+30^{1}right) &=70 times(0530 &=70 times frac{sqrt{3}}{2} end{aligned} )