Question

(P) Amount Borrowed ( =z 60,000 ) Rate ( y ) interest ( =5 % ) Amomet at the end ( f ) lyear ( =P #left(1+frac{R}{100}right) )
[
begin{array}{l}
=360,000left(1+frac{8}{180}right)
=60,00000 frac{21}{20}
=sum 6,3,000
end{array}
]
Amonut repaid at the erd of ( operatorname{ls} t ) year ( =frac{50}{100} times 60,000 )
[
=Z 30,000
]
( therefore ) Primeipal tor the 2 nd yem ( =sum 63,000-₹ 30,000 ) ( =bar{z} 33,000 )
Amount at the exd of ( 2^{text {the secold year }}left(1+frac{R}{100}right) )
[
begin{array}{l}
=sum 33,000left(1+frac{5}{100}right)
=533,060 times frac{21}{20}=1650
=₹ 34,650
end{array}
]
Amount repaid at the end of second ( 50 % ) of ( I 60,000=sum 30,000 ) year
( therefore ) Amount outstanding at the beginning of the
[
begin{aligned}
text { thind year } &=sum 34,650-sum 30,000
&=sum 4,650(text { ANs })
end{aligned}
]

# 9. Pramod borrowed 60,000 at 12% per annum compound interest. If he pays 50% of the sum borrowed at the end of the first year and 50% of the remaining loan at the end of the second year, find the amount of loan outstanding at the beginning of the third year.

Solution