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[
begin{array}{l}
1 d m^{3}=1 L
1 c m^{3}=10^{-3} L
end{array}
]
Equivalent -Molar mass ( 8 f N_{2}=22.4 mathrm{L} / 22.4 mathrm{dm}^{3} )
So, No of molecules ( y=frac{22.4 mathrm{cm}^{3}}{22.4 mathrm{dm}^{3}} eq 2 frac{2.4 times 10^{3} mathrm{dm}^{3} times mathrm{N}_{A}}{22.4 times 0 mathrm{dm}^{3}} )
[
begin{aligned}
N_{A}=6.022 times 10^{23} & leq 10^{-3} times 6.023 times 10^{23}
&=6.022 times 10^{20}
end{aligned}
]

# 9. The number of molecules in 22.4 cm of dinitrogen gas at STP is (a) 6.002 x 1020 (b) 6.022 x 1023 (c) 22.4 x 1020 (d) 22.4 x 1023

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