Question

(18. total No. If divisors ( 216 mathrm{u} ) o.
use ( varepsilon_{9}^{text {느 }} ) :
( d(n)=(a+1)(b+1)(c+1) )
Where ( d(h)= ) Nuin divitura ( a, b, c=varepsilon times ) ponints of prime factorizotion Huut: ( 21600=2^{5} times 5^{3} times 5^{2} )
( d(n)=(a+1)(b+1)(c+1) )
( d(21600)=(5+1)(3+1)(2+1) )
( a mid(21600)=6 times 4 times 3 )
( 1 d(216 w)=72 )
( int 0, quad ) totel allvisure id
( 72-2=70 )

# 92. Find the number of divisors of 21,600 excluding 1 and the number itself - (a) 72 (b) 142 (©) 35 (d) 70

Solution