Question

Ratio of area of 2 similan triangle ( = ) Ratio ( f ) squass
[
begin{array}{l}text { orvespending sid } Rightarrow frac{Delta A B C}{Delta P Q R}=frac{B C^{2}}{Q R^{2}}end{array}
]
( Rightarrow frac{sum 5}{49}=left(frac{B C}{9.8}right)^{2} )
( Rightarrow quad B C=7 )
( therefore ) conect option is ( (b) )

# 98. (d) TIO The area of two similar triangles ABC and POR are 25 cm2, 49 cm. If QR=9.8 cm, then BC is (a) 9.0 cm (b) 7 cm (c) 49 cm (d) 41 cm

Solution