Question

( T=sqrt{frac{2 h}{g}} )
at to ( T / 3 )
( S=frac{1}{2} g frac{T^{2}}{9} )
( begin{aligned} int_{x^{infty}}^{N^{2}} sin y &=frac{1}{18} cdot g cdot frac{2 h}{g}=frac{h}{9} text { from top. } &=h-frac{h}{9} text { fromgrement } end{aligned} )
( Rightarrow ) (c) 8 h/g fom ground

# A ball is released from the top of a tower of height h metres It takes T seconds to reach the ground. What is the position of the ball in T/3 seconds? [AICEE-2004) (A) h/9 metres from the ground (B) 71/9 metres from the ground (C) 8h/9 metres from the ground (D) 17/18 metres from the ground

Solution