A beaker contains 200gm of water. T...
Question
A beaker contains 200gm of water. The heat capacity of the beaker is equal to that of 20gm of water. The initial temperature of water in the beaker is 20∘C. If 440gm
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A beaker contains ( 200 mathrm{gm} ) of water. The heat capacity of the beaker is equal to that of ( 20 mathrm{gm} ) of water. The initial temperature of water in the beaker is ( 20^{circ} mathrm{C} ). If ( 440 mathrm{gm} ) of hot water at ( 92^{circ} mathrm{C} ) is poured in it, the final temperature, neglecting radiation loss, will be nearest to
(1) ( 58^{circ} mathrm{C} )
(2) ( 68^{circ} mathrm{C} )
(3) ( 73^{circ} mathrm{C} )
(4) ( 78^{circ} mathrm{C} )

JEE/Engineering Exams
Physics
Solution
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A beaker contains 200gm of water. The heat capacity of the beaker is equal to that of 20gm of water. The initial temperature of water in the beaker is 20∘C. If 440gm of hot water at 92∘C is poured in it, the final temperature, neglecting radiation loss, will be nearest to
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Heat lost by hot water = Heat gained by cold water in beaker + Heat absorbed
by
[
begin{array}{c}
440(92-theta)=200 times(theta-20)+20 times(theta-20)
p
end{array}
]
( T=68 circ C )

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