A biprism is placed 5 cm from slit ...
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A biprism is placed 5 cm from slit illuminated by sodium light of wavelength 5890 Ă. The width of the fringes obtained on a screen 75 cm from the biprism is 9.424 x 10-2 cm. What is the distance between two coherent sources?

NEET/Medical Exams
Physics
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[ d= ] fringes width. ( beta=frac{Delta lambda}{2 d} ) [ begin{array}{l} 2 d=frac{D lambda}{beta} 2 d=frac{75 times 5890 times 10^{-8}}{9.424 times 10^{-2}} =46875 times 10^{-6} 20=46875 mathrm{mcm} end{array} ] Teacher's Signature :
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