A block of mass 25 kg is raised by ...
Question  # A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in figure. What is the action on the floor by the man in the two cases? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding ? [NCERT) om lo noi super KOLMASA 25kg 25kg

JEE/Engineering Exams
Physics
Solution 152 4.0 (1 ratings)  ( 750 mathrm{N} ) and ( 250 mathrm{N} ) in the respective cases; Method (b) Mass of the block, ( m=25 mathrm{kg} ) Mass of the man, ( M=50 mathrm{kg} ) Acceleration due to gravity, ( mathrm{g}=10 mathrm{m} / mathrm{s}^{2} ) Force applied on the block, ( F=25 times 10=250 mathrm{N} ) Weight of the man, ( W=50 times 10=500 mathrm{N} ) Case (a): When the man lifts the block directly. In this case, the man applies a force in the upward direction. This increases his apparent weight. ( therefore ) Action on the floor by the man ( =250+500=750 mathrm{N} ) Case (b): When the man lifts the block using a pulley. In this case, the man applies a force in the downward direction. This decreases his apparent weight. ( therefore ) Action on the floor by the man ( =500-250=250 mathrm{N} ) If the floor can yield to a normal force of ( 700 mathrm{N} ), then the man should adopt the second method to easily lift the block by applying lesser force. Quick and Stepwise Solutions Just click and Send OVER 20 LAKH QUESTIONS ANSWERED Download App for Free