A body starts from the origin and m...
Question  # A body starts from the origin and moves along the X-axis such that the velocity at any instant is given by ( left(4 t^{3}-2 tright), ) where ( t ) is in second and velocity is in ( mathrm{m} / mathrm{s} ). What is acceleration of the particle, when it is at distance ( 2 mathrm{m} ) from the origin.

JEE/Engineering Exams
Physics
Solution 84 4.0 (1 ratings)  Velocity of the particle at any instant ( t, v=4 t^{3}- ) ( 2 t )
=> Acceleration at any instant t
( a=frac{d v}{d t}=12 t^{2}-2 )
Position of the particle at any instant t
( mathrm{dx}=left(4 mathrm{t}^{3}-2 mathrm{t}right) mathrm{dt} )
( int d x=intleft(4 t^{3}-2 tright) d t )
( =>x=t^{4}-t^{2} )
( mathrm{At} mathrm{x}=2 mathrm{m} )
( t^{4}-t^{2}-2=0 )
( =>left(t^{2}+1right)left(t^{2}-2right)=0 )
t cannot be imaginary, therefore, ( t^{2}=2 )
Substituting this value of ( t^{2} ) in equation (1)
( =>mathrm{a}=22 mathrm{m} / mathrm{s}^{2} ) Quick and Stepwise Solutions Just click and Send OVER 20 LAKH QUESTIONS ANSWERED Download App for Free