Question

# A charge of ( 1 mu C ) is given to one plate of a parallel-plate capacitor of capacitance ( 0 cdot 1 mu mathrm{F} ) and a charge of ( 2 mu mathrm{C} ) is given to the other plate. Find the potential difference developed between the plates.

Solution

To find, the potential difference we have to find inner charges. When charges in Capacitor an Equal and incur charges are equal and opposite.

[

begin{aligned}

text { lates charge } &=sum frac{operatorname{charg} e^{2 n}}{2}

&=frac{1+2}{2}

&=frac{3}{2} u C

end{aligned}

]

let charge inside ke ( 'x' ) but tetal charge on (1) is 1uc( C )

[

begin{array}{l}

Rightarrow frac{3}{2} u C+x=operatorname{In} C

quad Rightarrow x=-frac{1}{2}

end{array}

]

So inner chare ( =pm frac{1}{2} )

[

V=frac{q}{c}=frac{frac{1}{2}}{0.1}={sqrt{5 V} }{{} text {}}

]

is the answer