A charge of 1μC is given to one pla...
Question
A charge of 1μC is given to one plate of a parallel-plate capacitor of capacitance 0⋅1μF and a charge of 2μC is given to the other plate. Find the potential differen
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A charge of ( 1 mu C ) is given to one plate of a parallel-plate capacitor of capacitance ( 0 cdot 1 mu mathrm{F} ) and a charge of ( 2 mu mathrm{C} ) is given to the other plate. Find the potential difference developed between the plates.

JEE/Engineering Exams
Physics
Solution
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A charge of 1μC is given to one plate of a parallel-plate capacitor of capacitance 0⋅1μF and a charge of 2μC is given to the other plate. Find the potential difference developed between the plates.
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To find, the potential difference we have to find inner charges. When charges in Capacitor an Equal and incur charges are equal and opposite.
[
begin{aligned}
text { lates charge } &=sum frac{operatorname{charg} e^{2 n}}{2}
&=frac{1+2}{2}
&=frac{3}{2} u C
end{aligned}
]
let charge inside ke ( 'x' ) but tetal charge on (1) is 1uc( C )
[
begin{array}{l}
Rightarrow frac{3}{2} u C+x=operatorname{In} C
quad Rightarrow x=-frac{1}{2}
end{array}
]
So inner chare ( =pm frac{1}{2} )
[
V=frac{q}{c}=frac{frac{1}{2}}{0.1}={sqrt{5 V} }{{} text {}}
]
 is the answer

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