Question

Let Number of Articles ( =x ). cost of ( E a C h ) article ( =2 x+3 )
To tal cost = Number of Articles X cost of Each Article
[
begin{aligned}
90 &=x(2 x+3)
90 &=2 x^{2}+3 x
& 2 x^{2}+3 x-90=0
end{aligned}
]
( 2 x^{2}+15 x-124-90=0 )
( 2 x^{2}-12 x+15 x-90=0 )
( 2 x(x-6)+15(x-6)=0 )
( (x-6) cdot(2 x+15)=0 )
( x=6, quad x=frac{-15}{2} rightarrow ) If a cre
cannot be negatic
". Number of Articles = 6 cost of Each Article ( =15 )

# A cottage industry produces a certain number of pottery articles in a day. It was observed or a parucular day that the cost of production of each article in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was 90, find the number of articles produced and the cost of each article. 44 Solution

Solution