Question

According to Graham's law of diffusion,
( frac{r_{1}}{r_{2}}=sqrt{frac{M_{2}}{M_{1}}} )
( frac{1}{1 / 6}=sqrt{frac{M_{2}}{2}}( )rate of diffusion of
unknown gas is ( 1 / 6 ) and hydrogen
moleuclar mass( =2 )
( M_{2}=6^{2} times 2=72 )
Thus the formula of the gas is ( C_{5} H_{12}= ) ( 5 times 12+12 times 1=72 )

# A gas with molecular formula C.H26-2 diffuse through a porous plug at a rate of 1/6" of the rate of diffusion of H2 gas under similar condition. The formula of gas is (A) CHE (B) Grohn (C) CSH 12 (D) C6H14

Solution