Question

case I
( a=frac{F}{3 a} )
( N_{1}=m a )
( quad=m times frac{F}{3 a}=frac{F}{3} )
case II
( begin{aligned} a=& frac{F}{3 a} N_{2} &=2 m times a &=2 m times frac{F}{3 a}=frac{2}{3} F frac{N_{1}}{N_{2}} &=frac{1}{2} end{aligned} )
Hence ( c ) is the correct answer.

# a JUICUIQUUn Or normal reaction Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force Fis applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of force of contact between the two blocks will be : F- 2m 2m m (A) same (B) 1:2 (D) 1:3 (C) 2:1

Solution