Question

A lady has 25 p and 50 p coins in her purse. If in all she has 40 coins totalling 12.50, find the number of coins of each type she has.

IIT/JEE

Maths

Solution

4.0 (1 ratings)

Let no. of ( 25 mathrm{p} ) coins be ( -x ) Let no. ot ( 50 mathrm{p} ) coins be ( -mathrm{J} ) [ text { Total amount }=left{begin{array}{ll} 2 & 12.50 end{array}=1250 mathrm{P}right. ] ( n ) [ 25 x+50 y=1250 ] fiven that ( x+y=40 ) ( operatorname{saning} theta+4 ) In (1) livide ( 5 y^{2}=5 ) ( x-4^{2} y=50 ) Sduing ( (3)+(2 Rightarrow 3) ) ( x+2 y=50 ) [ begin{array}{l} frac{-x+y=40}{0+y=10} frac{y=10}{25 p operatorname{coins}=30}=frac{x=30}{5} end{array} ] SOP coins ( =10 )