A man borrows Rs. 4000 and agrees t...
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A man borrows Rs. 4000 and agrees to repay with a total interest of Rs. 680 in 12 monthly instalments. Each instalment being less than the preceding one by Rs. 20. Find the first instalment and the last instalment. (Ans: a = Rs 500, 1, = Rs 280)

11th - 12th Class
Maths
Solution
180
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Totol Amount fo be paid [ =4000+680=24680 ] Let man pays ( x ) in first month ( x-20 ) in second moth Total sum ( = ) [ begin{aligned} & x+(x-20)+(x-40)-ldots(x-220) =&(2 x-20(1+2 ldots 11) =& 12 x-frac{20 times 11 x^{6} / 2}{x}=4680 end{aligned} ] ( Rightarrow 12 x=6000 ) ( Rightarrow x=operatorname{sod}(text { first thatalonort }) ) last is ( (x-220) ) ( 0.500-220=(280) ) ansintallment [ text { Ans } 500,280 ]
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