Question

A measured temperature on fahrenheit scale is 200°F. What will this reading be on Celsius scale A on

JEE/Engineering Exams

Chemistry

Solution

200

1.0 (1 ratings)

( F=frac{9}{5} 6+12 ) ( left(frac{F-32}{9}right)^{5}=^{0} c ) ( left(frac{200-12}{9}right)^{5}=0 ) ( sqrt{2007}-frac{56+68}{9} times 8 ) ( frac{93280}{x}=0 ) ( 93.3 mathrm{c} )