Question

the the two metaf carborateg be ( Mleft(0,3, text { and } M^{*} cos _{3} cdot sigma_{n} ) heating right.
the roptep carbonates the reaction the t oceurs are:
( 44 g cos =60 g cos ^{-2} )
( 1 cdot 32 g cos =frac{60}{49} x_{1} cdot 32 )
( =1 cdot 8 mathrm{g} 0 mathrm{f} cdot mathrm{cos}^{2} )
troter rouss of ( C_{0}^{-2} ) is ( 2 cdot 8 ) g
( cdot mid cdot 0 gamma cdot cos ^{-2}=frac{1 cdot 8 times 100}{2 cdot 8}=64 cdot 28+ )
( +1-0.5 ) one ronetal ( =12 cdot 5 cdot mu )
( therefore ) H. 05 of ( 2 r ) ronetal
[
begin{array}{r}
=1.50-12.5-64.28
7.23 .22
end{array}
]
( 0,2+i 0 n(0) ) is correet

# A mineral consists of an equimolar mixture of the carbonates of two biva present to the extent of 12.5% by weight. 2.8 g of the mineral on heating lost 1:35 the % by weight of the other metal ? (A) 87.5 (B) 35.71 (C) 65.11 (D) 23.21 nates of two bivalent metals. One metal is 1 heating lost 1.32 g of CO,. What is

Solution