Question

A mineral consists of an equimolar mixture of the carbonates of two biva present to the extent of 12.5% by weight. 2.8 g of the mineral on heating lost 1:35 the % by weight of the other metal ? (A) 87.5 (B) 35.71 (C) 65.11 (D) 23.21 nates of two bivalent metals. One metal is 1 heating lost 1.32 g of CO,. What is

JEE/Engineering Exams

Chemistry

Solution

177

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the the two metaf carborateg be ( Mleft(0,3, text { and } M^{*} cos _{3} cdot sigma_{n} ) heating right. the roptep carbonates the reaction the t oceurs are: ( 44 g cos =60 g cos ^{-2} ) ( 1 cdot 32 g cos =frac{60}{49} x_{1} cdot 32 ) ( =1 cdot 8 mathrm{g} 0 mathrm{f} cdot mathrm{cos}^{2} ) troter rouss of ( C_{0}^{-2} ) is ( 2 cdot 8 ) g ( cdot mid cdot 0 gamma cdot cos ^{-2}=frac{1 cdot 8 times 100}{2 cdot 8}=64 cdot 28+ ) ( +1-0.5 ) one ronetal ( =12 cdot 5 cdot mu ) ( therefore ) H. 05 of ( 2 r ) ronetal [ begin{array}{r} =1.50-12.5-64.28 7.23 .22 end{array} ] ( 0,2+i 0 n(0) ) is correet