Question

A mixture of 2 moles of helium gas (atomic mass = 4 amu) and 1 mole of argon gas (atomic mass = 40 amu) is kept at 300K in a container. The ratio of their rms Vms (helium speeds Vms (argon)] 10.32 3 2.24 20.45 4 3.16

JEE/Engineering Exams

Physics

Solution

165

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Root mean square velocity - ( V_{r m s}=sqrt{frac{3 R T}{M}} ) ( =sqrt{frac{3 P}{rho}} ) wherein ( mathrm{R}= ) Universal gas constant ( mathrm{M}= ) molar mass ( mathrm{P}= ) pressure due to gas ( rho= ) density ( V_{r m s}=sqrt{frac{3 R T}{M}} ) ( frac{V_{r m s}(H e)}{V_{r m s}(A r)}=sqrt{frac{M_{A r}}{M_{H e}}}=sqrt{frac{40}{4}}=sqrt{10} ) ( =3.16 )