A particle is at rest at t = 0. If ...
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A particle is at rest at t = 0. If acceleration of the particle is given as a = sinnt + cosnt, in SI units, then the maximum speed of particle is 212 mis (1) = m/s (3) (V2+1) mis (4) ANZ mis TT 09456

JEE/Engineering Exams
Physics
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( a d t=0, quad v=0 ) [ a=sin pi t+cos pi z ] ( frac{d V}{d t}=sin pi t+cos pi t ) ( Rightarrow int d V=intleft(sin ^{pi} t+cos pi tright) d t ) ( Rightarrow quad v=frac{sin pi t-cos pi t}{pi}+c ) ad ( z=0, quad v=0 ) ( Rightarrow 0=-frac{1}{pi}+c Rightarrow c=frac{1}{pi} ) ( therefore quad V(t)=frac{sin pi z-cos pi t+1}{pi} ) ( V_{max } ) when ( frac{d V}{d t}=0 Rightarrow a=0 ) ( sin pi t+cos pi t=0 ) 2) tantt = ( pi t=frac{3 pi}{4} ) 2) ( quad t=23 / 4 ) ( m a x=sin 3 frac{pi}{4}-c d ) ( =frac{frac{1}{2}+frac{1}{2}}{pi}+1=frac{sqrt{2}+}{pi} )
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