Question

Intial velocity ( =v 1=5 mathrm{m} / ) seast
wards
[
wedge |^{wedge}
]
then after time t=10sec
Il towards
north ( 5 mathrm{m} / mathrm{s} )
( v 2=5 m / s ) north wards
[
Rightarrow Rightarrow Rightarrow Rightarrow Rightarrow
]
towards east ( 5 mathrm{m} / mathrm{s} )
Vresultant ( =sqrt{v} 1^{2}+v 2^{2} )
[
begin{array}{l}
=sqrt{2} 5+25
=5 sqrt{2}
end{array}
]
acceleration a=velocity/time
[
begin{array}{l}
=5 sqrt{2} / 10
=sqrt{2} / 2 times sqrt{2} / sqrt{2}
end{array}
]
( =1 / sqrt{2} ) towards ( n-w )

# A particle is moving eastwards with a velocity of 5 m/s in 10 seconds the velocity! northwards. The average acceleration in this time is 45 mis in 10 seconds the velocity changes to 5 ods [AIEEE-2005] (A) m/s towards north-east (B) -m/stowards north. (C) zero L (D) Tam/s² towards north-west

Solution