A particle moves along the straight...
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A particle moves along the straight line ( y=D ). The speed of the particle is ( v mathrm{m} / mathrm{s} ) towards right then
find ( frac{d theta}{d t} )
(1) ( frac{v}{D tan theta} )
(2) ( frac{v}{D} cos ^{2} theta )
(3) ( frac{v}{D} )
(4) ( frac{V}{sec ^{2} theta} )

JEE/Engineering Exams
Physics
Solution
220
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A particle moves along the straight line y=D. The speed of the particle is vm/s towards right then find
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( tan theta=frac{x}{D} Rightarrow x=D tan theta )
( quad frac{d x}{d t}=v )
( Rightarrow frac{d x}{d t}=frac{d}{d t}(D tan theta) )
( Rightarrow quad V=D sec ^{2} theta frac{d theta}{d t} )
( Rightarrow frac{d theta}{d t}=frac{v}{D sec ^{2} theta}=frac{v}{D} cos ^{2} theta )
( quad ) option (2)

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