Question

length of Rope is ( 10 mathrm{m} ) is dived 3 pieces
( x_{1}, x_{2}, x_{3} )
respectively ( x_{1}+x_{2}+x_{3}=10-0 )
Given ( begin{aligned} 2_{1} &=4 frac{1}{2}=frac{4 times 2+1}{2} &=frac{9}{2} m x_{2} &=3 frac{1}{5}=frac{3 times 5+1}{5} &=frac{16}{5} m end{aligned} )
( x_{1}, x_{2} )
values put
in equation ( frac{9}{2}+frac{16}{5}+x_{3}=10 )
( frac{9 times 5+16 times 2}{10}+x_{3}=10 )
( frac{17}{10}+x_{3}=10 )
( x_{3}=10-frac{77}{10} )
( x_{3}=frac{100-77}{10} )
( x_{3}=frac{23}{10} )
( x_{3}=2 cdot frac{3}{10} )

# A PIECE OF ROPE 10m LONG IS CUT INTO THREE PIECE IF THE LENGTH OF TWO PIECES IS_4m_AND 35 M RESPECTUM 70 THEN FIND THE LENITH OF THE THIRD PIECE.

Solution