A projectile is given an initial ve...
Question
A projectile is given an initial velocity of (i +27) m/s, where is along the ground and į is along the vertical. If g = 10 m/s?, the equation of its trajectory is
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A projectile is given an initial velocity of ( (i+2 i) mathrm{m} / mathrm{s} ), where ( i ) is along the ground and ( hat{j} ) is along the vertical.
If ( g=10 mathrm{m} / mathrm{s}^{2} ), the equation of its trajectory is:
[llT Main 2013]
(A) ( 4 y=2 x-25 x^{2} )
(B) ( y=x-5 x^{2} )
(C) ( y=2 x-5 x^{2} )
(D) ( 4 y=2 x-5 x^{2} )

JEE/Engineering Exams
Physics
Solution
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A projectile is given an initial velocity of (i +27) m/s, where is along the ground and į is along the vertical. If g = 10 m/s?, the equation of its trajectory is
Fullscreen

( U_{x}=I quad U_{Y}=2 quad tan theta 2 )
( y=n tan theta=frac{g x^{2}}{2 u^{2} cos ^{2} theta} quad u^{2}=5 )
( y=2 x-frac{10 x^{2} sec ^{2} theta}{10} )
( =2 x-x^{2}left(1+tan ^{2} alpharight) )
( y=2 x-5 x^{2}(c) ) Ans siverative

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