Question

A reaction rate constant is given by : 25000 k=12x10 4e I sec. It means : log k verses log T will give a straight line with a slope as 25000 log k verses log T will give a straight line with a slope as - 25000 log k verses T with give a straight line with a slope as - 25000 log k verses 1/T will give a straight line

JEE/Engineering Exams

Chemistry

Solution

117

4.0 (1 ratings)

( k=1.2 times 10^{14} e^{-25000} mathrm{k} ) ( log _{x rightarrow infty} frac{x-log (1 cdot 2 x log )}{70-2500 frac{1}{T}} ) ( (c) ) ( y=operatorname{man} 7 C ) ( m=-25000 ) ( x=1 / T )