Question

( k=1.2 times 10^{14} e^{-25000} mathrm{k} )
( log _{x rightarrow infty} frac{x-log (1 cdot 2 x log )}{70-2500 frac{1}{T}} )
( (c) )
( y=operatorname{man} 7 C )
( m=-25000 )
( x=1 / T )

# A reaction rate constant is given by : 25000 k=12x10 4e I sec. It means : log k verses log T will give a straight line with a slope as 25000 log k verses log T will give a straight line with a slope as - 25000 log k verses T with give a straight line with a slope as - 25000 log k verses 1/T will give a straight line

Solution