Question

A reaction rate constant is given by : 25000K k=12x104e I sec. It means : log k verses log T will give a straight line with a slope as 25000 log k verses log T will give a straight line with a slope as - 25000 log k verses T with give a straight line with a slope as - 25000 log k verses 1/T will give a straight line

JEE/Engineering Exams

Chemistry

Solution

4.0 (1 ratings)

( k=1 cdot 2 times 10^{14} e^{-2 frac{5000}{1}} mathrm{sec}^{1} ) Taking log" both sides ( omega g k=log 1 cdot 2 times 10^{19}+(-25000) ! frac{1}{1} sec ^{-1} ) ( log k quad vee B quad log T ) will give a hypersolic curve. ( (D) log k quad vee & quad frac{1}{pi} ) will give a Straight line option ( D ) i 8 wried